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why do i keep getting index exceeds matirx dimensions?

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parsh
parsh am 1 Apr. 2012
I just typed in simple codes for plotting a graph and i keep getting the same error why is that?
d=1:1:10
theta=pi/4;
Dc= d/2.*(1-cos(theta));
Q= (2.^(3/2).*Dc.^(5/2).*sqrt(g).*(theta-0.5.*sin(2.*theta)).^(3/2))/(8.*sqrt (sin(theta).*(1-cos(theta).^(5/2))))
subplot (2,1,2);
plot (d,Q)
title('17473981')
xlabel('diameter')
ylabel('flow rate')
grid on

Akzeptierte Antwort

the cyclist
the cyclist am 1 Apr. 2012
What is "g"? If I set g=1, your code works for me.
Might you have accidentally define your own variable named "cos", "sin", or "sqrt", so MATLAB thinks it is indexing a variable?
  4 Kommentare
parsh
parsh am 1 Apr. 2012
umm... it works. :) thank you so much
the cyclist
the cyclist am 1 Apr. 2012
Glad it worked, but that drastic solution does not necessarily help you understand where you went wrong. My best guess is that maybe you accidentally defined a new variable (maybe "xlabel") and MATLAB was trying to access that instead of the built-in function.

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Weitere Antworten (1)

Rick Rosson
Rick Rosson am 1 Apr. 2012
Please post the exact error message and indicate which line is triggering the error.
  3 Kommentare
Image Analyst
Image Analyst am 1 Apr. 2012
Funny - I get "Undefined function or variable 'g'."
parsh
parsh am 1 Apr. 2012
yeah i forgot to put in the value of g, my mistake. thanks you

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