Dipole antenna far-field pattern
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Vinci
am 22 Mai 2017
Beantwortet: Omkar Savkur
am 29 Jun. 2021
I need to plot the radiation pattern for a dipole antenna of length L=lambda/2. The example plot given was of L=1.4*lambda.
Example plot of L=1.4*lambda:

My code to try and reproduce the plot for L=1.4*lambda:
%Wavelength
lam = 1;
%Dipole antanna
L = 1.4*lam;
%Phase constant
B = 2*pi/lam;
t = 0:0.01:2*pi;
% Far-field pattern equation
E = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t));
figure()
polar(t,E)
Plot from this code:

I can't figure out where I'm going wrong with this one...
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Akzeptierte Antwort
David Goodmanson
am 22 Mai 2017
Hi Vinci, power is proportional to the square of the electric field, so if you use
E2 = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t)).^2;
figure()
polar(t,E2)
the correct figure should pop up.
Weitere Antworten (1)
Omkar Savkur
am 29 Jun. 2021
Hi Vinci, building off David's answer, you can use the polarpattern function to help plot the radiation power. You can interact with the plot and specify the plot parameters all in one line.
% Wavelength
lam = 1;
% Dipole antanna
L = 1.4*lam;
% Phase constant
B = 2*pi/lam;
% Angle in degrees
t = 0:0.1:360;
% Far-field pattern equation
E = abs((cos(B*L/2*cosd(t))-cos(B*L/2))./sind(t)).^2;
figure(1)
polarpattern(t,E,'AngleResolution',30)
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