How to fill the area between two curves on a polar plot?
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My code looks is below. I attached the two curves it generates, with the data that I have. How can I fill the space between the two curves?
t=data(1,:);
a1=data(11,:);
b1=data(12,:);
r_scale=50;
line_width=2;
font_size=12;
marker = 3;
figure(1)
polarplot(t,a1,'-or','MarkerSize',2)
hold on
polarplot(t,b1,'-ok','MarkerSize',2)
hold on
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Weitere Antworten (2)
Nate Roberts
am 27 Okt. 2021
Bearbeitet: Nate Roberts
am 28 Okt. 2021
I wrote a function that overlays a transparent cartesian axis over the polar axis. This may be cheating a little bit, but it gets the job done and looks nice:
theta = linspace(0,2*pi,180);
rho = 10*ones(size(theta));
f = figure('Color','White');
p = polarplot(theta,rho); rlim([0,15]);
polarfill(gca,theta,rho-normrnd(2,0.2,size(rho)),rho+normrnd(2,0.2,size(rho)),'blue',0.6)
function polarfill(ax_polar,theta,rlow,rhigh,color,alpha)
ax_cart = axes();
ax_cart.Position = ax_polar.Position;
[xl,yl] = pol2cart(theta,rlow);
[xh,yh] = pol2cart(fliplr(theta),fliplr(rhigh));
fill([xl,xh],[yl,yh],color,'FaceAlpha',alpha,'EdgeAlpha',0);
xlim(ax_cart,[-max(get(ax_polar,'RLim')),max(get(ax_polar,'RLim'))]);
ylim(ax_cart,[-max(get(ax_polar,'RLim')),max(get(ax_polar,'RLim'))]);
axis square; set(ax_cart,'visible','off');
end
See also my answer to a similar question. It is a more general solution than the one posted here: https://www.mathworks.com/matlabcentral/answers/325599-fill-area-between-two-polar-curves#answer_818408
1 Kommentar
Arthur Vieira
am 20 Jun. 2022
This solution seems nice but causes me issues. 1. I can't for instance save the figure as doing so will save the figure with just the fill in a cartesian axis. Can only take pictures with PrintScreen. 2. I can't 'hold on' after the fill has been added to plot more stuff. I'd actually like to plot two lines and two fills in the same figure.
Walter Roberson
am 18 Mai 2017
0 Stimmen
Unfortunately that does not appear to be possible. surface() and patch() specifically reject being children of PolarAxes; and fill() and area() and mesh() [none of which are primitives] fail when calling newplot() with newplot() rejecting making a cartesian child of a polar axes.
The actual drawing of polarplot() is by calling plot(), the implementation of which is now private.
3 Kommentare
Benjamin Cowen
am 18 Mai 2017
Bearbeitet: Walter Roberson
am 18 Mai 2017
Walter Roberson
am 18 Mai 2017
That code works by not using a polarplot() with its polaraxes(): it expects the user to use polar() which uses cartesian axes underneath it, and then it use patch() with cartesian coordinates.
Benjamin Cowen
am 18 Mai 2017
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