Sorting

3 Ansichten (letzte 30 Tage)
CHAITANYA PRASAD
CHAITANYA PRASAD am 30 Mär. 2012
I have 'line' matrix as follows :
line(1,m)= 1 2 3 4 5 6 7 8 9 10
line(2,m)=1.3 -2.3 4.245 12.3 -4.5 9.43 8.34 -5.3 3.54 6.4
I want to sort 2nd row in descend order, but 1st row as follows:
line(1,m)= 4 6 7 10 3 9 1 2 5 8
line(2,m)=12.3 9.43 8.34 6.4 4.245 3.54 1.3 -2.3 -4.5 -5.3

Antworten (2)

Andrei Bobrov
Andrei Bobrov am 30 Mär. 2012
l = [1 2 3 4 5 6 7 8 9 10
1.3 -2.3 4.245 12.3 -4.5 9.43 8.34 -5.3 3.54 6.4];
solution
[i1,i1] = sort(l(2,:),'descend');
out = l(:,i1)
OR
out = sortrows(l.',-2).'
  1 Kommentar
CHAITANYA PRASAD
CHAITANYA PRASAD am 1 Apr. 2012
Thank u Bobrov...It was very helpful..:)

Melden Sie sich an, um zu kommentieren.


C.J. Harris
C.J. Harris am 30 Mär. 2012
line(1,:)= [1 2 3 4 5 6 7 8 9 10];
line(2,:)= [1.3 -2.3 4.245 12.3 -4.5 9.43 8.34 -5.3 3.54 6.4];
[line(2,:), line(1,:)] = sort(line(2,:),'descend');
You also shouldn't really use 'line' as a variable name, since this is also an inbuild function, and might cause confusion if you don't clear the variable after use.
  1 Kommentar
CHAITANYA PRASAD
CHAITANYA PRASAD am 1 Apr. 2012
Thank u Chris...Actually i was using linerank...just for example i gave line...and it was very useful...:)

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Data Types finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by