How to empty part of column?

Say I have an column array that looks something like this:

A = [1:10]'

A =

1

2

3

4

5

6

7

8

9

10

If I wanted to get rid of 3 to 8, what would be the command?

Answer 1

[the cyclist]

A(A>=3 & A<=8) = [];

[the cyclist]

Note that this will remove elements with values equal to 3-8, not the elements in positions 3-8. (Your example is ambiguous about which of these you want.)

Answer 2

[the cyclist]

A(3:8) = [];

[the cyclist]

Note that this will remove positions 3-8, not elements with values equal to 3-8. (Your example is ambiguous about which of these you want.)

[Seong Nam]

So I Just created a column array that looks something like this;

I = [200:-2:-300] '

I tried using your solution:

I(196:2:-296) = [ ]

This doesn't seem to do anything. I do not see anything happening in the command window

[Walter Roberson]

196:2:-296 is the empty vector. When you use a positive increment (or use the default increment of 1) then if the last value is less than the first value, the result will be empty.

If you were to code

I(196:-2:-296) = [ ]

then 196:-2:-296 would not be empty, but you cannot use negative values as subscripts.

You probably want

I(I <= 196 & I >= -296) = [];

[Seong Nam]

This helped. Thank you!