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Replace the indexes of duplicate values

1 Ansicht (letzte 30 Tage)
Yesbol
Yesbol am 24 Apr. 2017
Beantwortet: RST am 14 Mai 2024
I have a matrix B 1631x5.
Columns 2 and 3 represent X and Y coordinates respectively.
I want to identify the indexes where B(i+k,2)==B(i+j,2)&B(i+k,3)==B(i+j,3). Note that there can be more than one duplicate.
Below is the script of identifying the duplicates:
%%X coordinate
[~, indX] = unique(B(:, 2), 'rows');
% duplicate indices
duplicate_indX = setdiff(1:size(B, 1), indX);
% duplicate values
duplicate_valueX = B(duplicate_indX, 2);
%%Y coordinate
[~, indY] = unique(B(:, 3), 'rows');
% duplicate indices
duplicate_indY = setdiff(1:size(B, 1), indY);
% duplicate values
duplicate_valueY = B(duplicate_indY, 3);
%%Both coordinates
duplicate_ind=intersect(duplicate_indX,duplicate_indY);
duplicate_value = B(duplicate_ind, 2:3);
When the code is executed, we get 2 matrix: duplicate_ind(1x149) and duplicate_value(149x2).
Let's consider first 4 values of duplicate_ind as an example:
>> duplicate_ind(1:4)
ans =
61 77 106 111
The corresponding values for these indexes are
>> duplicate_value(1:4,:)
ans =
355.3035 176.9755
364.7316 182.2644
354.4987 202.1553
350.5895 226.7602
Now I can find the original and the duplicate:
find(B(:,2)==duplicate_value(1,1))
ans =
1
61
>> find(B(:,2)==duplicate_value(2,1))
ans =
57
77
In this case, the index of the original value is 1 and the index of duplicate is 61. In other case: original: 57 and duplicate:77.
Now, I want to replace the indexes of the duplicates by the original ones. In our case 61 will be replaced by 1 (and 77 will be replaced by 57). Considering above, I want to build a matrix which has the size 1631x3 (must have the same number of rows as matrix B), where the 1st row represents the line number, 2nd and 3rd row - the coordinates of points.
The output is expected to look like:
1 1 2
2 2 3
3 3 4
...
57 57 58
...
61 1 62
...
77 57 78
78 78 79
...

Akzeptierte Antwort

Yesbol
Yesbol am 24 Apr. 2017
Solved
%%X coordinate
[~, indX] = unique(B(:, 2), 'rows');
% duplicate indices
duplicate_indX = setdiff(1:size(B, 1), indX);
% duplicate values
duplicate_valueX = B(duplicate_indX, 2);
%%Y coordinate
[~, indY] = unique(B(:, 3), 'rows');
% duplicate indices
duplicate_indY = setdiff(1:size(B, 1), indY);
% duplicate values
duplicate_valueY = B(duplicate_indY, 3);
%%Both coordinates
duplicate_ind=intersect(duplicate_indX,duplicate_indY);
duplicate_value = B(duplicate_ind, 2:3);
indexes=zeros(3,size(duplicate_value,1));
for i=1:size(duplicate_value,1)
if size(find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2)),1)==2
indexes(1:2,i)=find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2));
end
if size(find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2)),1)==3
indexes(1:3,i)=find(B(:,2)==duplicate_value(i,1)&B(:,3)==duplicate_value(i,2));
end
end
for j=1:size(B,1)-1
lines(j,1:2)=j;
lines(j,3)=j+1;
end
for j=1:size(lines,1)
for i=1:1:size(indexes,2)
if indexes(3,i)==0
if lines(j,2)==indexes(2,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(2,i)
lines(j,3)=indexes(1,i);
end
end
if indexes(3,i)~=0
if lines(j,2)==indexes(3,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(3,i)
lines(j,3)=indexes(1,i);
end
if lines(j,2)==indexes(2,i)
lines(j,2)=indexes(1,i);
end
if lines(j,3)==indexes(2,i)
lines(j,3)=indexes(1,i);
end
end
end
end

Weitere Antworten (1)

RST
RST am 14 Mai 2024
Try this:
[~,ixu,ixb] = unique(B(:,2:3),'rows'); % indices of unique rows for columns 2 and 3
ixd = setdiff(1:size(B,1), ixu); % (duplicate rows) = (all rows) - (unique rows)
fprintf("There are %d duplicate points\n", numel(ixd))
% make a copy of the data
C = B;
% for each duplicate
for iixd=ixd
% get indices of the matching rows
% fd = find( all(B(:,2:3)==B(iixd,2:3), 2) );
fd = find(ixb == ixb(iixd));
% overwrite 2nd and subsequent matching rows with the first
C(fd(2:end),:) = repmat( B(fd(1),:), ...
numel(fd)-1, 1);
end
clear fd, iixd, ixd, ixb, ixu

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