How can I access the previous index of a vector?

Hello friends,

I am trying to write a code to generate random vectors. Some of the variables are integer whereas a few are real numbers. Following is the code:

xL=[1 500 1 500];

xU=[37 1400 37 1400];

Xint=[1 3];

nvar=4;

for xV=1:nvar

if Xint(xV)==xV

         InPoP(:,xV) = randi([xL(xV) xU(xV)],Popu_size,1); 

      else

InPoP(:,xV) = (xU(xV)-xL(xV)).*rand(Popu_size,1) + xL(xV);

    end

end

Xint vector shows that first and third elements should be generated as integer. The problem is when the loop moves away from x=2. It cannot access the elements of Xint to know the number. I would be grateful if someone can share the solution of the problem.

Regards

[KSSV]

You have in Xint only two numbers and you are trying to access four numbers out of it. Make Xint to have four numbers i.e include few more numbers.

[Khalid Khawaja]

How can I write a program to generate Xint variables integer using iterative schemes?

Answer 1

[Walter Roberson]

Change

if Xint(xV)==xV

to

if ismember(xV, Xint)

[Khalid Khawaja]

Thank you very much for the answer. I was looking for exactly the same thing. Regards

Answer 2

[Roger Stafford]

You don’t appear to use ‘Xint’ for any other purpose than deciding whether to use integers or reals. Therefore I suggest you change it to:

   Xint = [1 0 1 0];
   for xV=1:nvar
     if Xint(xV) == 1
       % Use integers
     else
       % Use reals
     end

[Khalid Khawaja]

Thank you for your answer. It is also a good solution. Actually, I need Xint values for further operations. Changing the values to binary will need many changes in my code. Regards