# Increase nonzero values without deleting zeros

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monmatlab am 12 Apr. 2017
Kommentiert: David J. Mack am 12 Apr. 2017
I have a vector X.
X=[0 0 0 0 1 1 1 1 0 0 0 0 0 0 2 2 2 2 2 2 0 0 0 3 3 3 3 0 0 0 0 0 4 4 4]
I want to increase the values of the nonzero elements in vector X by 10 However, when I do this using the find function I end up just having a vector without the zeros.
Y=X((find(X~=0)))+10;
Y=[11 11 11 11 22 22 ... ]
Is there a way to do this without using a for loop?
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KSSV am 12 Apr. 2017
Where you want to place the non zeros numbers?
monmatlab am 12 Apr. 2017
Bearbeitet: monmatlab am 12 Apr. 2017
at their initial positions. I want to have the same vector , just with the nonzeros increased by ten

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### Akzeptierte Antwort

David J. Mack am 12 Apr. 2017
Bearbeitet: David J. Mack am 12 Apr. 2017
Hey monmatlab, simply use logical indexing:
Y = X;
isNonzero = X~=0;
Y(isNonzero) = 10*Y(isNonzero);
or the more compact inplace replacement:
X(X~=0) = 10*X(X~=0);
Greetings, David
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Adam am 12 Apr. 2017
If this is what you actually want to do, with multiplication then you can just skip the logical part and use
X = X * 10
since multiplying by 0 is 0 anyway! I was under the impression you wanted to add 10, not multiply by it though.
David J. Mack am 12 Apr. 2017
Ah true, the OP stated to increase it... but it's the same idea anyway. Just replace the * by a +.

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### Weitere Antworten (1)

Adam am 12 Apr. 2017
X = ( X ~= 0 ) .* ( X + 10 );
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