financial time series obiect: get a column by name string?

3 Ansichten (letzte 30 Tage)
Andy
Andy am 17 Mär. 2017
Bearbeitet: Andy am 17 Mär. 2017
Say, I have a fts object of type:
dt =
desc: (none)
freq: Daily (1)
'dates: (2715)' 'times: (2715)' 'A: (2715)' 'B: (2715)' 'C: (2715)'
to access a column, you'd do something like:
dt.A
What if you'd want to place this in a function and pass the column name as a string argument:
col_name = 'A'
Is there a way to access this column from dt having its name in a string?

Akzeptierte Antwort

dpb
dpb am 17 Mär. 2017
Again, similarly to the other question, relate it to the struct; I didn't find the similar documentation under the financial TS link, but here is link for structures; should work the same way...
  1 Kommentar
Andy
Andy am 17 Mär. 2017
Bearbeitet: Andy am 17 Mär. 2017
it works indeed:
dt.Close
cl = 'Close'
dt.(cl)
produce similar results. Thanks!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Characters and Strings finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by