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Split Column into 3 Columns

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Colin Starker on 9 Mar 2017
Answered: Alexandra Harkai on 9 Mar 2017
I have a matrix of size 1181X4. The first column in the original matrix is dates and I need to separate the first column into 3 columns that contain year, month, and day, respectively. The first column contains
20130101 20130102 20130103 20130104 20130105 ...(etc)
I need to split the first column into 3 columns so that column 1 contains:
2013 2013 2013 2013 2013 ...(etc)
(Note: the first column is not all 2013, it changes farther down.)
Column 2 should contain:
01 01 01 01 01 ...(etc)
(Note: like column 1, the values do change farther down)
Column 3 should look like:
01 02 03 04 05 ...(etc)

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Answers (1)

Alexandra Harkai on 9 Mar 2017
If your 1181*4 matrix is m:
res = [floor(m(:,1)/10000), floor(mod(m(:,1), 10000)/100), (m(:,1))];
Alternatively, you can treat them as dates, and go from numbers to character arrays and then back to numbers:
res = datevec(num2str(m(:,1)), 'yyyymmdd');
res = res(1:3,:); % take only the first 3 columns
m(:,1) is the first column of the input matrix.
Note that these will give 3, not '03', as the result will be a numeric array.

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