set the threshold value by percentage

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muhammad faiz
muhammad faiz on 22 Feb 2017
Commented: Jan on 23 Feb 2017
Hi, if i have 2 matrices A and B. A=rand(1,2) B=rand(10,2)
how do i find a point B where the distance to points A is closest, and i do not what the min value (distances). i would like to find something like "find distances that is higher 30 percent than the min value of the distances". please, how to do just that?
thank you.

Answers (1)

Jan
Jan on 22 Feb 2017
Edited: Jan on 22 Feb 2017
Start with finding the distances:
A = rand(1,2);
B = rand(10,2);
Dist = sqrt(sum((A - B).^2, 2));
Then determine the minimum and add 30%:
searched = min(Dist) * 1.3;
Now search the distance, which is nearest to searched:
[~, Index] = min(abs(Dist - searched));
Finally Index is the row of B, which is nearest to 130% of the minimum distance.
  2 Comments
Jan
Jan on 23 Feb 2017
This depends on the data. If the value, which is nearest to 130% is the nearest to 150% also, you get the same index. The smaller B is, the higher is the chance to get the same result for e.g. 130% and 140%. Try it with B = rand(1000, 2).

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