Creating matrix outside for loop

I need to create a matrix of variables and have the current code below. Is there anyway to do this without a for loop?

   x = 0:.1:1;
   y = 0:.1:1;
   for i = 1:length(x)
      for j = 1:length(y)
         x2(i,j) = x(i);
         y2(i,j) = y(j);
      end
   end

Answer 1

[Star Strider]

Try this:

x2 = y'*ones(size(x));
y2 = ones(size(y'))*x;

EDIT —

The R2016b multiplication automatically does the expansion. Previous versions would require bsxfun calls:

x2 = bsxfun(@times, y', ones(size(x)));
y2 = bsxfun(@times, ones(size(y')), x);

[m13]

Thank you! Now I have another question along the same lines. Is there a way to simplify the code below. Both x1 and y1 will change in the for loop.

for i = 2:length(x)-1
   for j = 2:length(y)-1
      x1 = x(i);
      y1 = y(j);

[Star Strider]

My pleasure!

MATLAB vectorised addressing will work here. You don’t need the loops.

Providing the dimensions are appropriate:

i = 2:length(x)-1
j = 2:length(y)-1
x1 = x(i);
y1 = y(j);

For example:

x =  11:17
i = 2:length(x)-1;
xp = x(i)

x =
    11    12    13    14    15    16    17

xp =
    12    13    14    15    16

[Akira Agata]

Another solution for the original question.

x = 0:.1:1;
y = 0:.1:1;
x2 = repmat(x',1,length(y));
y2 = repmat(y,length(x),1);

[m13]

Star if I need to use the y1 value in another for loop does this still work? I tried it and now I'm getting the error that the number of elements must be the same. The for loop is:

for k = 1:n
   U(k) = sin(y1);
end

[Star Strider]

You do not need the loop.

This works:

U = sin(y1);

(I apologise for the delay.)