Error when using ode45 command,"returns a vector of length 11, but the length of initial conditions vector is 1."

9 Ansichten (letzte 30 Tage)
function dw_dt = equation_(t,w)
a = 1;
b = 1.35;
v= [.6:.01:.70].';
dw_dt = a*w.^(v)-b*w;
%actual script
time_period = [0 20];% time period between 0 and 20 weeks
w0 = 0.5;% intial weight of the fish
[t,w] = ode45('equation_',time_period,w0);
I'm trying to run my function using ode45. I should be able to run the function for every value of yv but for some reason i can't. when ever i try to run the function for once value of V is works perfectly fine but when i try to run it for every value of v it does not work well.

Akzeptierte Antwort

John Chilleri
John Chilleri am 7 Feb. 2017
Bearbeitet: John Chilleri am 7 Feb. 2017
Hello,
The way the ode45 command works (as I'm sure you know) is that given a state vector, in your case w, you provide a function that evaluates the derivative of w and returns dw.
A common example is with position and velocity:
state_vec = [position; velocity];
where as your 'equation_' would return:
dstate_vec = [velocity; acceleration];
it seems like you understand this; however, you are giving it an initial condition of .5, so:
w = .5;
then you are returning a dw that is a vector (because v is a vector and is apart of the computation).
So ode45 is trying to update a constant .5 with a vector dw, this is where you are encountering your error. You can fix this by either changing your dw to a scalar result, or making your initial condition an equally long vector corresponding to the length of the returned dw.
Hope this helps!

Weitere Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by