Q=0.25;
L=5;
a=1-cos(2*pi*D1/fn);
x=(pi*D1)/(fn*L)*sin(2*pi*D1/fn);
y=cos(2*pi*D1/fn)*((4*Q/pi*fn)+((pi^2*D1/fn^2*L)*(0.5-D1))-1);
z=(pi^2*D1/fn^2*L)*(0.5-D1);
m=4*Q/pi*fn;
deno=1+x+y+z+m;
Gdc1=a/deno;
Hi I want to plot a surface of Gdc where D1=0.1:0.1:0.5 and fn=0.5:0.1:1.5
How can I do it?

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 25 Jan. 2017

0 Stimmen

Q = 0.25;
L = 5;
[D1, fn] = ndgrid(0.1:0.1:0.5, 0.5:0.1:1.5);
D1_fn = D1./fn; %optimization
a = 1 - cos(2*pi*D1_fn);
x = (pi*D1) ./ (fn*L) .* sin(2*pi*D1_fn);
y = cos(2*pi*D1_fn) .* ((4*Q/pi*fn) + ((pi^2*D1_fn./fn*L) .* (0.5-D1)) - 1);
z = (pi^2*D1_fn./fn*L) .* (0.5-D1);
m = 4*Q/pi * fn;
deno = 1+x+y+z+m;
Gdc1 = a ./ deno;
surf(D1, fn, Gdc1, 'edgecolor', 'none')

3 Kommentare

safi58
safi58 am 25 Jan. 2017
Hi Walter, is it possible to do plotting like this figure?
Walter Roberson
Walter Roberson am 25 Jan. 2017
surf(D1, fn, Gdc1)
Your plot is course because 0.1:0.1:0.5 is course. You should probably use a finer resolution. For example,
N = 20;
[D1, fn] = ndgrid(linspace(0.1,0.5,N), linspace(0.5,1.5,N));
safi58
safi58 am 26 Jan. 2017
thank you so much

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu 2-D and 3-D Plots finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 25 Jan. 2017

Kommentiert:

am 26 Jan. 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by