Hi everyone,
I have a cell (called AA ) that contains 1 row * 36 columns (as shown in the attached image)
As we could see that each column in that cell contains 3 values ( means inside each column there are 1*3)
I need to have an array that has 36 Rows * 3 columns
For example,
the first column in the Cell will be converted into 1 Row and three columns, the second column in the Cell will be converted in the same way and finally add all of them together in order to generate an array that contains 36 Rows and 3 Columns
as shown in this example
-1.48247427405830e-15 0.185513882360673 -0.185513882360676
-9.59200039657764e-16 0.211729497802758 -0.211729497802760
3.69087930153418e-16 0.224791092084074 -0.224791092084073
Really appreciate any help
Regards.

 Akzeptierte Antwort

the cyclist
the cyclist am 10 Jan. 2017

1 Stimme

I think this does what you want
reshape(cell2mat(AA'),36,3)

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 10 Jan. 2017

2 Stimmen

This can be done much more simply as
vertcat(A{:})

1 Kommentar

the cyclist
the cyclist am 10 Jan. 2017
That's twice in one day that I've been schooled by Walter.

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