How to calculate the value of polynomial value for 150 coefficient.It is not possible to use polyval function.
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I try this
for k=1:150
x=x1(k);
fprintf('============')
sum1=0;
b=0;
for i=1:2
b=b+B1(i)*power(x,i) ;
sum1=sum1+b;
end
final(i)=10000+sum1;
end
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Antworten (1)
Walter Roberson
am 25 Dez. 2016
final = 10000 + B1(1) * x1(1:150) + B1(2) * x1(1:150).^2 ;
This can be written as
final = 10000 + B1(1) * x1 + B1(2) * x1.^2 ;
if x1 is exactly 150 items long.
5 Kommentare
John D'Errico
am 25 Dez. 2016
Bearbeitet: John D'Errico
am 25 Dez. 2016
It will "work". It will produce complete garbage. But that is a completely different issue, as you well know.
Walter Roberson
am 26 Dez. 2016
Yep. And unless the user happens to have pure integer coefficients and pure integer x values, it is not clear that they could meaningfully get anything other than garbage (at least not with less than 1800 decimal places results.)
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