Save each column of a matrix in a seperate .csv file

I was wondering how to write this code in a more elegant way. Basically, I want to save each column of the sample matrix in a separate .csv file. I wanted do this in a for loop, but it is not clear for me how to give each filename an index, because Channel(i).csv ,is just considered to be the filename without index

channel1=sample(:,1);save Channel1.csv channel1 -ASCII;
channel2=sample(:,2);save Channel1.csv channel2 -ASCII;
channel3=sample(:,3);save Channel1.csv channel3 -ASCII;
channel4=sample(:,4);save Channel1.csv channel4 -ASCII;
channel5=sample(:,5);save Channel1.csv channel5 -ASCII;
channel6=sample(:,6);save Channel1.csv channel6 -ASCII;
...
...
....
channel15=sample(:,15);save Channel1.csv channel15 -ASCII;
channel16=sample(:,16);save Channel1.csv channel16 -ASCII;

Answer 1

[per isakson]

• "save each column of the sample matrix in a separate .csv file" &nbsp e.g. Channel01, Channel02, etc.
• "how to give each filename an index" &nbsp make the number part of the name, e.g. sprintf('Channel%02d.csv',jj). The leading zero, "0", makes the files appear in the "correct" order in file listings.
• I prefer fprintf over save to write text

sample  = [ magic(6); magic(6) ];  % Create sample data
len     = size( sample, 2 );
folder  = 'h:\m\cssm';
for jj = 1 : len
    ffs = fullfile( folder, sprintf('Channel%02d.csv',jj) );
    fid = fopen( ffs, 'w' );
    fprintf( fid, '%f\n', sample(:,jj) );
    fclose( fid );
end

[monmatlab]

Thank you!