Using conditional IF statement

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summyia qamar
summyia qamar am 19 Dez. 2016
Beantwortet: Steven Lord am 19 Dez. 2016
I have a matrix A and I generate B=randi([0,1],7,3).I want C=A*B only if sum of each row of B=1..I tried this..
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1]
for k=1:numIterations
B=randi([0,1],7,3);
if sum(B,2)==1;
C=A*B;
end
end
how to use IF condition in this case?
  2 Kommentare
Walter Roberson
Walter Roberson am 19 Dez. 2016
What do you want to have happen if the condition is met multiple times within the "for k" loop? You are overwriting all of C each time.
summyia qamar
summyia qamar am 19 Dez. 2016
thankyou..I skipped C(k)

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Akzeptierte Antwort

Roger Stafford
Roger Stafford am 19 Dez. 2016
if all(sum(B,2)==1)
  1 Kommentar
summyia qamar
summyia qamar am 19 Dez. 2016
I tried this.
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1];
for k=1:numIterations
B=randi([0,1],7,3);
if all(sum(B,2)==1)
C=A*B
end
end
[B C(ones(7,1))]
and result is C =
1 2 1
0 4 0
2 1 0
2 1 0
1 1 1
0 2 1
ans =
0 0 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 0 1 1
1 0 0 1
0 0 1 1
row 3 is not upto the condition

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Weitere Antworten (1)

Steven Lord
Steven Lord am 19 Dez. 2016
Don't generate B randomly, or at least not the way you're generating it. Your constraint on B is that each row must have exactly one nonzero value. So generate the index of the column in each row that contains the nonzero value and use that to generate a B matrix that is guaranteed to satisfy your constraint.
numRows = 10;
numCols = 5;
rowind = (1:numRows).';
colind = randi(numCols, numRows, 1);
B = accumarray([rowind, colind], 1, [numRows, numCols]);
check = all(sum(B, 2) == 1)
The sz input to accumarray is necessary for the (unlikely) case where no row has a 1 in the last column, to ensure B is the correct size.

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