Morton scanning ?

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vishnu
vishnu am 9 Mär. 2012
Geschlossen: Walter Roberson am 3 Jan. 2017
i am long days itslef looking for morton scanning . but i do not suceed to create morton matrix for an image ...
here is some code for 4*4 which i referred ..
clc;
clear all;
close all ;
n=2;
ind=morton(n);
a=reshape(1:4^n,2^n,2^n);
disp(a)here is the matlab function
function ind=morton(n);
% MORTON(N) return the morton permutation order for array of size 2^N
% e.g.
% n=2;
% matrix size is 2^n
% ind=morton(n);
% d=fix(rand(2^n,2^n)*10);
% disp(d)
% disp(d(ind))
linind4=(1:4^n)-1; %start index count for array at zero
ind4str=dec2base(linind4,4); %convert indices to base-4
b1=dec2bin(str2num(ind4str(:,1))); %split each base-4 into two base-2numbers
b2=dec2bin(str2num(ind4str(:,2)));
rb=[b1(:,1) b2(:,1)]; %the rows are given by the first bits of b1 and
b2
cb=[b1(:,2) b2(:,2)]; %the columns are given by the second bits of b1 and b2
r=bin2dec(rb)+1; %convert the row from bit to decimal
c=bin2dec(cb)+1; %convert column
ind=[2^n*(c-1)+r]'; %make a linear row index into array for easyaddressing
%morton.m ends
if any one knows how to create for a image please help me
  5 Kommentare
vishnu
vishnu am 15 Mär. 2012
its an urgent work please
Walter Roberson
Walter Roberson am 20 Mär. 2012
http://www.mathworks.com/matlabcentral/answers/29922-why-your-question-is-not-urgent-or-an-emergency

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