I have 4 arrays of 335 elements each, i want one array(resultant) whcih consists of first array element in first element and first array element of second array into second element of resultant array and first array element of third array into third

eg: a=[1;2;3] b=[4;5;6] c=[7;8;9]

and i want d=[1;4;7;2;5;8;3;6;9]

please help me out,

Answer 1

[bio lim]

Like this?

a=[1;2;3];
b=[4;5;6];
c=[7;8;9];
d = [a';b';c'];
d = reshape(d, [9 1]);

Output:

d =

       1
       4
       7
       2
       5
       8
       3
       6
       9

[Mohammed Yousuf]

for 3X3 matrix it works, i said i have 335 elements in my array., 3 element array was an example.., anthing using for loop is appreciable.., please. urgent

[KSSV]

Don't say urgent: You said you have 4 arrays of 335 element. Clarify your self.

[Mohammed Yousuf]

sorry, sir it is, 4 column vectors each carry 335 elements, eg: x=(335,1) y=(335,1) z=(335,1) w=(335,1), among this i need a column 'a' vector whcih consist of first element of x, as a first element of 'a', then first element of 'y' as a second element of 'a', then first element of 'z' as a third element of 'a',and first element of 'w' as a fourth element of 'a' then repeat as so on

[Mohammed Yousuf]

second element of 'a' must be second element of x,y,z,w as so on

[KSSV]

Check the answer....below.

[bio lim]

It's still the same approach.

a=rand(335,1);
b=rand(335,1);
c=rand(335,1);
d=rand(335,1);

e=[a';b';c';d'];
e = reshape(e, [1340 1]);

Answer 2

[KSSV]

clc; clear all ;
a=[1;2;3] ;
b=[4;5;6] ;
c=[7;8;9] ;
abc = [a b c]' ;
iwant = abc(:)

[KSSV]

   x=rand(335,1) ;
   y=rand(335,1) ;
   z=rand(335,1) ;
   w=rand(335,1) ;
   xyzw = [x y z w]' ;
  iwant = xyzw(:) ;