matrix multipication per elements and convert to char

hi, any solution with this matrix multipication??

pop =

     9     0    -2     3    -4     
     8    -9     1     0    -3    
     7    -8     9    -1     2    
     6    -7     8    -9     1

if pop > 0,

m = [2*pop-1 2*pop; 2*pop 2*pop-1];

elseif pop == 0

m = [2*i+1 pop;2*i-1 pop]; % i is number of row's

elseif pop < 0,

m = [2*pop+1 2*pop; 2*pop 2*pop+1];

end

here's a resul's what i need:

    17  18    2   0    -3  -4    5   6   -7 -8    
    18  17    1   0    -4  -3    6   5   -8 -7    

    15  16   -17  18    2   2    4   0   -5 -6    
    16  15   -18 -17    2   2    3   0   -6 -5    

    13  14   -16 -16    17  18  -2  -2    3  4    
    14  13   -16 -16    18  17  -2  -2    4  3    

    11  12   -14 -14    16  16  -17 -18   1  2    
    12  11   -14 -14    16  16  -18 -17   2  1

i appreciate a lot for any attention.. thx before

[Friedrich]

If pop is really the matrix above, than none of the formulas for m will generate the matrix you want. Could you explain a bit more how the resulting matrix should be generated? So which laws should be applied on the input matrix?

In addition, your if else brance is never true at all, e.g. this will display never the word true:

if pop > 0

disp('true')

elseif pop == 0

disp('true')

elseif pop < 0

disp('true')

end

So what do you want achive exactly?

[Jan]

There was a very similar question some days ago - it used "a" instead of "pop". But I cannot find it anymore. Has it been deleted to increase our confusion?

The operation should happen elementwise, so each element is replaced by [2*pop(i,j)-1, 2*pop(i,j); 2*pop(i,j), 2*pop(i,j)-1]

[mashudi]

no, i didn't.. it just delete while i try to delete doubled recent post's, since i got a new formula for my research so i need a new solutions..

here's the answer from andrei bobrov on my previous question

out = cell2mat(arrayfun(@(pop)[2*pop 2*pop; 2*pop 2*pop],pop,'un',0));

and

k = @(pop)[2*pop-1 2*pop; 2*pop 2*pop-1];

out = blockproc(pop,[1 1],@(block_struct)k(block_struct.data))

he answer for 3 solutions but the last one is lost.

pardon me, it makes confuse on you. .

[mashudi]

so far, this is the solutions i have

out = cell2mat(arrayfun(@(pop)[2*pop 2*pop; 2*pop 2*pop],pop,'un',0));

[row, col]= size(out);

for b= 1:row

for k= 1:col

if out(b,k) > 0

if mod((b + k),2)== 0

out(b,k)= out(b,k)-1;

end

elseif out(b,k) == 0 && mod(k ,2)== 1

if mod(b ,2)== 1

out(b,k)= b + 1;

else

out(b,k)= b - 1;

end

else

if mod((b + k),2)== 0 && out(b,k) < 0

out(b,k)= out(b,k)+1;

end

end

out2=[out -out];

end

end