Question on how to calculate the variance and then standard deviation on an interval from a to b with 100 samples of size 225 random numbers

      nsamples=100;

      samplenum = 1:nsamples;

        %setting number of samples and the sample amt. i.e. here there 
        %is only 1 sample of number 100

      n = 225;
        
        %sample size 225

      a = 1;

        %setting first mean value of 1

      b = 2;

        %setting second mean value of 2

a + (b-a)*rand()

  %gives uniform random values in the interval [a,b]

    ((b-a)^2)/100

      %calculating variance

    d = (b-a)/sqrt(100)
      
      %calculating standard deviation

Hi, so here I am wondering to calculate the variance and standard deviation should i be using:

(samplenum) instead of (b-a)?

I'm trying to generate 100 samples and then find the standard deviation

Also this part of the code:

c = (b+a)/2
  
  %calculating mean of values of mean between a and b

should be calculating the mean values between a and b?

Thank you!

Answer 1

[Image Analyst]

Why not use mean(), var(), and std()?

Your c is not using any actual values. You need to do something like

data = a + (b-a)*rand(1, nsamples);
cMean = mean(data)
cStdDev = std(data)

[HrMmz]

oh sorry i'm entirely new to MATLAB, thank you