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Addition of time series' values in array

3 Ansichten (letzte 30 Tage)
David
David am 6 Mär. 2012
Hello,
I have a tricky one I haven't been able to solve. I have an array of objects of a specific class. One of the properties of this class is a time series. I can guarantee that all the time series for that particular property for all objects in the array have exactly the same time vector. I would like to sum all the values of that property (i.e. of those time series) into a single time series with the same time vector.
For example, I have an array OBJECTS composed of objects of class OBJ with property PROP of type timeseries. I want to add all the data values of the PROP time series.
I tried the following:
sum(OBJECTS(:).PROP.Data)
but didn't work. I'm not sure about the OBJECTS(:) part, in particular the (:). I made several different tests, also playing with the dimension for sum (first or second) but without success.
Any ideas? Thanks in advance for any suggestion.
  1 Kommentar
per isakson
per isakson am 6 Mär. 2012
What happend? Did you get an error message?

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Antworten (2)

Laurens Bakker
Laurens Bakker am 7 Mär. 2012
Why not just use a for loop?
sum = zeros( size(OBJECTS(1).PROP.Data );
for obj=OBJECTS
sum = sum + obj.PROP.Data;
end
  1 Kommentar
David
David am 13 Mär. 2012
I am currently using a loop as a work-around, but I was hoping to use SUM as it should be much faster. But thanks for the suggestion.

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owr
owr am 13 Mär. 2012
The double level of "." indexing could cause an issue, but if it was just single level this trick might work:
>> foo(1).data = rand(5,1);
>> foo(2).data = rand(5,1);
>> foo(:).data
ans =
0.7577
0.7431
0.3922
0.6555
0.1712
ans =
0.7060
0.0318
0.2769
0.0462
0.0971
>> [foo(:).data]
ans =
0.7577 0.7060
0.7431 0.0318
0.3922 0.2769
0.6555 0.0462
0.1712 0.0971
>> sum([foo(:).data],2)
ans =
1.4638
0.7750
0.6692
0.7016
0.2683

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