loop for matlab array
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i have a problem with for loop.we have a vector a=[0 1 1 1 0] and a vector b=[1 1 1 1 1]
for i = 1:length(a)
if a(i)==0
c = [-1.*b] ;
else if a(i)==1
c = [1.* b];
end
end
the loop works only for a(1)=0 and stops.
Antworten (3)
Geoff Hayes
am 23 Nov. 2016
Try removing the space between the else if. Re-write this as
if a(i)==0
c = [-1.*b] ;
elseif a(i)==1
c = [1.* b];
end
4 Kommentare
best16 programmer
am 23 Nov. 2016
Image Analyst
am 23 Nov. 2016
What are you trying to do? Each iteration you make up a c array which is different on each iteration. c is not a single number you know. It's a vector.
best16 programmer
am 23 Nov. 2016
Image Analyst
am 23 Nov. 2016
Then just do
handles.edit1.String = sprintf('%d ', c);
This will convert the vector to a string and put it into the edit text box on your GUI.
Image Analyst
am 23 Nov. 2016
Maybe you wanted elseif instead of "else if". This works and does several iterations:
a=[0 1 1 1 0]
b=[1 1 1 1 1]
for i = 1:length(a)
if a(i)==0
c = [-1.*b]
elseif a(i)==1
c = [1.* b]
end
end
Of course there are better ways to do that and no experienced MATLAB programmer would do that operation like that.
3 Kommentare
best16 programmer
am 23 Nov. 2016
Bearbeitet: best16 programmer
am 23 Nov. 2016
best16 programmer
am 23 Nov. 2016
Image Analyst
am 23 Nov. 2016
They will all be displayed because there is no semicolon at the end of the line. Did you actually try it and look in the command window?
Andrei Bobrov
am 23 Nov. 2016
c = (a(:)*2 - 1)*b(:)';
or
c = (a(:)*2 - 1).*b(:);
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