Double integral error Matrix dimensions must agree
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I have a problem with computing a double integral. My code so far is:
B = 5;
L0 = 0:10;
A0 = 0:10;
tau = 1:100;
% Open and read the file
fid = fopen('first.txt', 'r');
data = cell2mat(textscan(fid, '%d'));
data = dlmread('first.txt');
% Two columns in the file
% First corresponds to time
t = data(:,1);
% Second to data values for luminosity
d = data(:,2);
% Posteriors for the three models 0,1&2
p0 = ((1./sqrt(2.*pi))^10).*(exp(-sum(0.5.*(d-B).^2)));
p1 =@(L0)((1./sqrt(2.*pi))^10).*(exp(-sum(0.5.*(d-B-L0).^2)));
p2 = @(A0,tau)((1./sqrt(2.*pi))^10).*(exp(-sum(0.5.*(d-B-A0.*exp(-t/tau)).^2)));
I1 = integral (p1, 0,10);
I2 = integral2 (p2,0, 10, 1, 100);
fclose(fid);
It seems to work fine for the normal integral I1 but crashes for the double integral I2. Any suggestions? ps. Sorry for the long equations
In the file, I have this:
0 7.108842
1 5.360705
2 5.871565
3 4.441087
4 6.877640
5 6.049399
6 5.587317
7 6.687828
8 7.390521
9 5.646180
2 Kommentare
Daniel kiracofe
am 13 Nov. 2016
Suggest that you post the actual error message and the first.txt data file. "crashes" is not very descriptive, and without the data we cannot try the code.
Emily Takeva
am 13 Nov. 2016
Akzeptierte Antwort
Weitere Antworten (1)
Roger Stafford
am 13 Nov. 2016
Bearbeitet: Roger Stafford
am 13 Nov. 2016
0 Stimmen
1. In the expression for ‘p2’ you have “t/tau” which is matrix division. However the sizes of ’t’ and ‘tau’ are incompatible with matrix division. Probably you need -t./tau.’ . (That's a transpose operator on tau to make it a column vector.)
2. I also have serious doubts about the validity of taking the sum in calculating both ‘p1’ and ‘p2’. It makes a very strange kind of integrand. You are already summing over your data in obtaining each individual integrand value as ‘L0’ and ‘A0’ vary.
3. Also why did you define ‘L0’ and ‘A0’ as vectors earlier, while using the same symbols for arguments in ‘p1’ and ‘p2’? It suggests some kind of erroneous thinking in 2. above.
2 Kommentare
Emily Takeva
am 13 Nov. 2016
Roger Stafford
am 14 Nov. 2016
Did you transpose tau as I specified using tau.'?
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