I have a cell (NewCell {1,1}) with 1 column and many rows, each row has or '0' or []. If its '0', I want to make a comparison; if its the other thing, i want a 'V'.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
teste2 = cell(size(catconsumo));
for k=2:(length(Preos2013S1)-1)
if NewCell{1,1}{k} == '0'
mask = strcmp(catracio1, 'low') & strcmp(catpreco, 'high');
teste2(mask) = {'A'};
mask = strcmp(catracio1, 'medium low') & strcmp(catpreco, 'medium high');
teste2(mask) = {'B'};
mask = strcmp(catracio1, 'medium') & strcmp(catpreco, 'medium');
teste2(mask) = {'C'};
mask = strcmp(catracio1, 'medium high') & strcmp(catpreco, 'medium low');
teste2(mask) = {'D'};
mask = strcmp(catracio1, 'high') & strcmp(catpreco, 'low');
teste2(mask) = {'E'};
elseif NewCell{1,1}{k} ~= '0'
teste2{k}='V';
end
end
However, teste2 results with [] in every row, or one of those letters, but regardless of there is a [] or a '0' in NewCell{1,1}. Its not respecting the 'if' condition. Can somebody help me please?
1 Kommentar
bemin
am 8 Nov. 2016
You need to give little more details about your cell, However What I see from your code that you are trying to compare number with a string so you ether use strcmp () or write the if without quotations just like this:-
if NewCell{1,1}{k} == 0
...
...
..
etc.
I hope I can help
Antworten (1)
James Tursa
am 8 Nov. 2016
Bearbeitet: James Tursa
am 8 Nov. 2016
elseif isempty(NewCell{1,1}{k})
The problem you are having is that the result of NewCell{1,1}{k} ~= '0' is empty in that branch, not true, so you don't get into the elseif block.
Or, if you know for sure that there are only '0' and [] in NewCell{1,1}{k}, you could just turn that entire elseif statement into an else. E.g.,
else
teste2{k}='V';
1 Kommentar
Siehe auch
Kategorien
Mehr zu Characters and Strings finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!