how to get the specific member data from a struct array?

5 Ansichten (letzte 30 Tage)
xiao
xiao am 4 Nov. 2016
for example,
b=struct('name','JPEG','age','18') ;
c=repmat(b,3,1) ;
d=c.name;
c.name
why is the result of "c.name" different from the result of "d=c.name"?
how to get the member data directly from a struct array or matrix? such as c.name?
and another question, how to create a struct array or matrix directly just like zeros(2,3), but struct(2,3) doesn't work, so how?

Akzeptierte Antwort

George
George am 4 Nov. 2016
From the doc on struct
"When you access a field of a nonscalar structure, such as s.f, MATLAB® returns a comma-separated list. In this case, s.f is equivalent to s(1).f, s(2).f, s(3).f."
So your d = c.name is equivalent to
d = c(1).name, c(2).name, c(3).name.
Try
[d,e,f] = c.name
to see the difference. See here for more info on how to access data in a struct.
struct(2,3) doesn't work because it's trying to create a 1x1 struct array with field:2 and value:3. Field needs to be a char array.
  1 Kommentar
xiao
xiao am 5 Nov. 2016
thank you! inspired by you, i try d = [c(1).name, c(2).name, c(3).name] and
d=[c.name] for a large struct to put the result together, but need to redivide
the result array. so maybe for loop is required.
and to create a struct matrix, maybe the for loop method or repmat way is needed.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Alexandra Harkai
Alexandra Harkai am 4 Nov. 2016
Bearbeitet: Alexandra Harkai am 4 Nov. 2016
What c is is what is called a nonscalar struct array. Then "You cannot assign the list to a single variable with the syntax v = s.f because the fields can contain different types of data." as per the Documentation, so variable d gets only c(1).name, and hence they will be different.
  2 Kommentare
xiao
xiao am 5 Nov. 2016
Bearbeitet: xiao am 5 Nov. 2016
thx! so, for loop method is required to get the data of a struct array or matrix?
Alexandra Harkai
Alexandra Harkai am 7 Nov. 2016
Please do not change your question once it has been answered, it is preferred to start new one.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Structures finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by