Sir, i cant get u, divided_Array = mat2cell(myarray, [85 85], [85 85], 36);how to find max value for 4 halves in each image from that result?

1 Ansicht (letzte 30 Tage)
kaavya subramani
kaavya subramani am 1 Nov. 2016
Beantwortet: Walter Roberson am 1 Nov. 2016
plz help me

Melden Sie sich an, um diese Frage zu beantworten.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 1 Nov. 2016
For any one block indexed at J, K,
max(max(divided_Array{J,K},1),2)
The result of this expression would be size 1 x 1 x 36 . You can put the parts together to get your final result.

Weitere Antworten (0)

Kategorien

Mehr zu Image Processing Toolbox finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by