I have an error in using bvp4c, my result is wrong
My task is to solve
3*y"+2*y'=x
y(0)=-2
y(1)=6
my matlab code:
dydt=@(x,y)[y(2); y(2)+x];
bc=@(ya,yb)[ya(1)+2; yb(1)-6];
yinit=@(x)[exp(-x); -exp(-x)];
solinit=bvpinit(linspace(0,1,20),yinit);
sol=bvp4c(dydt,bc,solinit);
plot(sol.x,sol.y(1,:))
Could you help me to find what wrong?

Antworten (1)

Bill Greene
Bill Greene am 30 Okt. 2016

0 Stimmen

I think you want: dydt=@(x,y)[y(2); (x-2*y(2))/3];

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am 29 Okt. 2016

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am 30 Okt. 2016

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