gridding problems in the script
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Vadim Tambovtsev
am 27 Okt. 2016
Beantwortet: KSSV
am 27 Okt. 2016
Hello,
in the task I have an independent-of-grid "real size" set of good sand inside a volume. The task is to make gridding on this set, convert in to 100x50x50 grid, to 64x32x32 grid etc.
I managed to make this script, but the "good-sand" fractions differs a lot depending on the chosen grid, but it should be almost the same. Could you find an error in my script?

Thank you.
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KSSV
am 27 Okt. 2016
A is dependent on what variables? Specifically do you have x and y values for the grid?
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KSSV
am 27 Okt. 2016
You can reduce your A of size 100x50x50 to 64x32x32 using the following code:
%%do spatial inteprolation to reduce A spatially
[m,n,p] = size(A) ;
x = linspace(0,1,n) ;
y = linspace(0,1,m) ;
[X,Y] = meshgrid(x,y) ;
% Reduce A spatially
xi = linspace(0,1,32) ;
yi = linspace(0,1,64) ;
[Xi,Yi] = meshgrid(xi,yi) ;
%
Ar = zeros(64,32,p) ;
for i = 1:p
Ar(:,:,i) = interp2(X,Y,A(:,:,i),Xi,Yi) ;
end
%%Reduce thrid dimension
t = linspace(0,1,p) ;
ti = linspace(0,1,32) ;
Areduced = zeros(64,32,32) ;
for i = 1:64
for j = 1:32
Arij = squeeze(Ar(i,j,:)) ;
Areducedij = interp1(t,Arij,ti) ;
% replace values
Areduced(i,j,:) = Areducedij ;
end
end
Areduced is your A with new dimensions of 64X32X32.
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