Filter löschen
Filter löschen

Help with an error

1 Ansicht (letzte 30 Tage)
Ali
Ali am 1 Mär. 2012
Hello,
I want to ask you how can I solve such an error.
The thing is I want a 2-D array that grows.
x has a length n and is a column vector
L is an nxn vector
this is the prototype of the code.
I cant figure out a way to solve such a question
function [Nt,xe,ye]= PopulationProgress(x,L)
%x=[200000,300000,500,1500]'
i=0;
n=length(x);
Nt=Zeros(n,3);
Nt(:,1)=x;
Nt(:,2)=L*Nt(:,1);
while Nt(:,i)= Nt(:,i+1)
i=i+1;
Nt(:,i)=L*Nt(:,i-1);
Nt(:,i+1)=L*Nt(:,i);
end;
ye=i;
xe=Nt(:,i);
Thank you for any suggestions
Best

Akzeptierte Antwort

Srinivas
Srinivas am 1 Mär. 2012
MATLAB is case sensitive, replace your
Nt = zeros(n,3)
i = 1,
MATLAB does not allow indices to be '0';

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 1 Mär. 2012
In your "while" statement, you need to use "==" rather than "="
  1 Kommentar
Ali
Ali am 1 Mär. 2012
Yup, I figured it out. Yet still I am getting an error.
I don't know why.
Nt=Zeros(n,3);
Nt(:,1)=x; have the same size
I am not sure about the syntax of the coding though.
I want the column to be equal to x.
Is this how am I supposed to do it?

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by