Problem with the im2uint16
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Efstathios Kontolatis
am 13 Okt. 2016
Kommentiert: Efstathios Kontolatis
am 13 Okt. 2016
I need to create a series of mean images. So I created the following code
function [meanbgimage] = impostprocbg(bgpath)
%Calculates the mean backgroung image
cd(bgpath)
bglist=dir('*.tif');
I0 = imread(bglist(1).name);
sumbgImage = im2double(I0); % Inialize to first image.
k=1;
for i=2:length(bglist) % Read in remaining images
nameused = bglist(i).name;
img = imread(nameused);
% Image = imcomplement(Image);
img=im2double(img);
% img=wiener2(img);
sumbgImage = im2double(imadd(sumbgImage,img));
clear img
if mod(i,100)==0
meanbgimage(:,:,k) = imdivide(sumbgImage,100);
j = meanbgimage(:,:,k);
j = im2uint16(j);
meanbgimage(:,:,k) = j;
sumbgImage = zeros(512,512);
k=k+1;
end
i
end;
The problem is that I need meanbgimage to be an array of uint16 2D arrays. However, this code returns meanbgimage as a double. Does anybody knows what should I do?
0 Kommentare
Akzeptierte Antwort
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Convert Image Type finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!