I have a system of 3 linear equations with 2 variables. I can solve it by substitution but not with linsolve.

3*x/5+y/5=x
2*x/5+0.8*y=y
x+y=1

Answer 1

[Oddur Bjarnason]

I found the answer to my question:

3*x/5+y/5=x 2*x/5+0.8*y=y x+y=1

3*x/5-5/5*x+y/5=0 2*x/5+4/5*y-5/5*y=0 x+y=1

-2/5*x+y/5=0 2/5*x-1/5*y=0 x+y=1

A=[-2/5,1/5;2/5,-1/5;1,1] B=[0;0;1] linsolve(A,B)

ans = 0.3333 0.6667