Given a matrix A = [2 5 7; 4 1 8], write a for loop that will replace all the even numbers with 0.
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Sydney
am 7 Okt. 2016
Beantwortet: Andrei Bobrov
am 7 Okt. 2016
I'm looking for something using a for loop (probably nested) and possibly mod(A,2) to determine the even numbers
What I tried: It took me a while to figure out how to format mod, but once I did I started with: for b=mod(A,2) I think tried to add a logical function (such as b==0) but it kept giving me errors. The closest thing that I could write that made sense in my head was:
for b=mod(A,2);
if b==0
A(b)=0
end
end
I would then get the error: Subscript indices must either be real positive integers or logicals.
I also couldn't figure out how to size a matrix to be the same size as a different matrix.
3 Kommentare
Akzeptierte Antwort
Mohammad Haghighat
am 7 Okt. 2016
This can be a solution using for loops:
[m,n] = size(A);
for i = 1:m
for j = 1:n
if mod(A(i,j),2) == 0
A(i,j) = 0;
end
end
end
2 Kommentare
James Tursa
am 7 Okt. 2016
This is obviously a homework post. It is discouraged to do homework problems for others on this forum. Helping OP with concepts, correcting their code, etc is all within the spirit of this forum. But doing the entire problem outright for them is not.
Weitere Antworten (1)
Andrei Bobrov
am 7 Okt. 2016
A(rem(A,2)==0)=0;
or with loop
for ii = 1:numel(A)
if rem(A(ii),2) == 0
A(ii) == 0;
end
end
0 Kommentare
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!