I am trying to display a plot in customary units if x = 0 or the same plot in metric units if x = 1. However, no matter whether I enter 0 or 1 for x, the program returns only the metric plot. The customary plot works fine if I take out that part of the code and run it separately. Am I missing something in the syntax?
prompt = ' Enter 0 for customary units or 1 for metric units: ';
x = input(prompt);
if x == '0';
disp(Tcust);
sc = [custWS1; custWS2; custWS3; custWS4; custWS5; custWS6; custWS7; custWS8; custWS9; custWS10];
hc = [3; 8; 13; 33; 55; 155; 245; 382; 519; 656];
semilogy(sc,hc);
title('Boundary Layer Plot');
xlabel('Wind Speed, mph');
ylabel('Height, ft');
else x == '1';
disp(Tmet);
sm = [metWS1; metWS2; metWS3; metWS4; metWS5; metWS6; metWS7; metWS8; metWS9; metWS10];
hm=[0.9; 2.44; 3.96; 10; 16.8; 47.2; 74.7; 116; 158; 200];
semilogy(sm,hm);
title('Boundary Layer Plot');
xlabel('Wind Speed, m/s');
ylabel('Height, m');
end

 Akzeptierte Antwort

Star Strider
Star Strider am 29 Sep. 2016

0 Stimmen

In:
x = input(prompt);
‘x’ is a double-precision numeric value, not a string, so:
if x == '0'
will always return false.
Try this:
if x == 0
and:
elseif x == 1
and see if those changes do what you want.

4 Kommentare

kelsey young
kelsey young am 29 Sep. 2016
Hey, thanks for the input.
I tried elseif instead of else and now the program returns nothing when it runs, whether I enter 0 or 1. Nothing happens.
My pleasure.
This emulates your if block, and returns the appropriate resluts:
x = input('Give me an ‘x’! ');
if x == 0
fprintf(1, 'x is 0\n')
elseif x == 1
fprintf(1, 'x is 1\n')
end
Give me an ‘x’! 0
x is 0
Give me an ‘x’! 1
x is 1
I can’t run your code, so testing the if block (successfully) is the best I can do.
It works.
kelsey young
kelsey young am 29 Sep. 2016
On second glance, I realized I missed your point about x not being a string. I changed that and the elseif statement worked perfectly. Thank you so much!
Star Strider
Star Strider am 29 Sep. 2016
As always, my pleasure!

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