random signal delay

2 Ansichten (letzte 30 Tage)
zozo
zozo am 27 Feb. 2012
Beantwortet: vijay am 31 Okt. 2013
clc
clear all
close all
fs=10000; % sampling frequency in Hz
f1=500; % frequency of signal in Hz
f2=200;
f3=700;
t_duration=1; %duration of LONG signal in seconds
t = 0:1/fs:t_duration-1/fs; %sampling points
x = sin(2*pi*f1*t)+cos(2*pi*f2*t)+sin(2*pi*f3*t);
d=0.000079734452; % time delay in seconds
I can delay it mathematically as follows:
s1=sin(2*pi*f1*(t-d))+cos(2*pi*f2*(t-d))+sin(2*pi*f3*(t-d));
How can I do the same (mathematically) if:
x=randn(size(t));
I need to produce the same set of random values each time. I have gone through doc rng; but Iam unable to do it.
Please illustrate with an example.
thank you.

Antworten (2)

Honglei Chen
Honglei Chen am 27 Feb. 2012
There are two questions in your post so I'm not sure if I understand exactly what you look for. I'll include my thoughts below:
1. To get the same random value each time, set a seed using rng, for example
rng(1);
randn(10,1);
rng(1);
randn(10,1);
You should get the same random values for two trials.
2. Now if you want to delay the random signal, you can always append zero in front. The number of zeros you insert depends on your sampling frequency and required delay.
x = randn(10,1);
x_delay = [0;x]; % delayed by 1 sample
  4 Kommentare
zozo
zozo am 27 Feb. 2012
Ok..Can you suggest an alternative test, apart from the one I used above in my code?
Honglei Chen
Honglei Chen am 27 Feb. 2012
Personally I think your test case is fine, if you really want, you can try a triangle signal or even a rectangular signal. Just be prepared that there will be distortion in the result.

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vijay
vijay am 31 Okt. 2013
do u have modified code for this

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