how to remove last characther from cell array of string

Hi All, let's say i have this cell array of string:

test={'1234T'; '4567T'; '8901T'};

Is the a way to remove the last character T on every cell using this kind of command:

test=test{:}(1:end-1);

If not what is the best way to do it without loop? Cheers Medie

[Mederic Mainson]

Hi, I think i found the best way...

test= cellfun(@(x) x(1:end-1), test, 'UniformOutput', false);

Is it the best way?

[Walter Roberson]

It is a good way. Depending how large the array is, it is possible that regexprep might be faster on large matrices; I would need to benchmark to verify that though.

Answer 1

[Walter Roberson]

I have not looked at all carefully, but if you are using R2016b then I gather the new string data type has functions that can be used for this kind of thing without using a loop.

Other than that there are multiple ways. The easiest is probably

test = cellfun(@(S) S(1:end-1), test, 'Uniform', 0);

which uses an implicit loop.

You could also use

test = regexprep(test, '.$', '', 'lineanchors');

which means "replace the character right before the end of string with nothingness"