what is my problem in using datevec?

cd('C:\Users\Kwom\Desktop');
% I loaded my folder
file=xlsread('Week02_climate_data_analysis.xls');
% I loaded my Excel file in my folder. - 14244x5 double
% in the excel file, the column is date (ex. 19730101) the row is temperature, humidity...etc.
% my purpose is to separate the spring(March~May), summer(June~August), fall(September~November), winter(December~February) by using 'datevec' in Excel's column.
% So, I made these ones...
date=num2str(file(:,1));
dateformat='yyyy,mm,dd';
datevec(date,dateformat)
However, it has a error... I don't know what is a problem...
What should I do...?

1 Kommentar

Stephen23
Stephen23 am 21 Sep. 2016
Bearbeitet: Stephen23 am 21 Sep. 2016
"What should I do...?"
Use the correct date format string:
>> datevec('19730101','yyyymmdd')
ans =
1973 1 1 0 0 0

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Antworten (1)

Saurabh Gupta
Saurabh Gupta am 21 Sep. 2016

0 Stimmen

Hello Ryoung,
Based on your description, it seems that your date values are in the format 'yyyymmdd' (ex. 19730101), but you are using the date format as ‘yyyy,mm,dd’ for the datevec function. Your ‘dateformat’ string should match the date format in your ‘date’ string (i.e. the format of the date values in your source file).

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Gefragt:

am 18 Sep. 2016

Bearbeitet:

am 21 Sep. 2016

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