Find the indices of elements of matrix that were multiplied
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a task to find the maximum product of elements in a matrix. The input arguments are the matrix and the scalar n that tells me how many elements to multiply. If n=2, then I should multiply two by two. The maximum product can lie either in rows, or in columns on in diagonal. For example in this case A's elements were multiplied 2 by 2 along rows (B) and columns (C).
A =
8 1 6
3 5 7
4 9 2
B =
8.0000 6.0000
15.0000 35.0000
36.0000 18.0000
C =
24.0000 5.0000 42.0000
12.0000 45.0000 14.0000
I do it using the loop
c=[]
for ii = 1:(length(A)-n+1)
p = prod(A(:,ii:ii+n-1));
c=[c p];
end
or
for i=1:size(A,2)
B(i,:)=real(exp(conv(log(A(i,:)),ones(1,n),'valid')));
C(:,i)=real(exp(conv(log(A(:,i)),ones(1,n),'valid')));
end
In both cases I receive the product but when it comes to getting the maximum among that products, (in my case that is the product of A(3,1)*A(3,2)=45) I cannot find the indices of original matrix elements that formed that product. Any help will be appreciated.
0 Kommentare
Antworten (1)
Andrei Bobrov
am 15 Sep. 2016
A =[ 8 1 6
3 5 7
4 9 2];
n = 2;
s = size(A);
B = real(exp(conv2(log(A),ones(1,n),'valid')));
C = real(exp(conv2(log(A),ones(n,1),'valid')));
[b,bm] = max(B(:));
[c,cm] = max(C(:));
if b > c
[ii,jb] = ind2sub([s(1),s(2) - n + 1],bm);
out = {ii,jb + (0:n-1)};
else
[ic,jj] = ind2sub([s(1) - n + 1,s(2)],cm);
out = {ic + (0:n-1),jj};
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!