Filter löschen
Filter löschen

value replacement in an array

2 Ansichten (letzte 30 Tage)
Yazdan Kordestany
Yazdan Kordestany am 9 Sep. 2016
Kommentiert: Star Strider am 9 Sep. 2016
Hi all,
I have a big 2D array and I want to change some of their values. So, I am using A(A==value)=value2. However, it just works for some specific values, for instance it works, when A(A==7.843120581576564e-04) = 1, but I cannot change it when A(A==0.183079763461368)=2. could the decimal be the reason?
Thanks, Yaz

Akzeptierte Antwort

Star Strider
Star Strider am 9 Sep. 2016
My guess is that it’s not an exact match for the value in ‘A’. See Why is 0.3 - 0.2 - 0.1 (or similar) not equal to zero? for an explanation of one possible reason.
  2 Kommentare
Yazdan Kordestany
Yazdan Kordestany am 9 Sep. 2016
Thanks Star, I checked and you were right. However, I was not able to solve it yet, so I used excel instead and load it on matlab.
Star Strider
Star Strider am 9 Sep. 2016
My pleasure.
If the value already exists in ‘A’ and you want to find other instances of it, use the existing value to compare, since it is likely to have the necessary precision.
Another option is to set a range:
A = 0.183079763461368;
A(A>=0.183079763461367 & A<=0.183079763461369)=2;
This runs without error and sets the single value of ‘A’ here to 2. You will need to experiment with it in your code to see if it does what you want.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by