HOW TO TAKE AVERAGE OF ROW AND COLUMN AT SOME POINT
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abdul wahab aziz
am 24 Aug. 2016
Kommentiert: abdul wahab aziz
am 24 Aug. 2016
I HAVE A MATRIX
2 5 3 500 4 5,
3 4 2 2 3 5,
4 5 5 1 2 2
code must scan first where 500 exists and take average of that row and column wher 500 exists excluding that 500,
here ans should be like avg row at first 2+5+3+4+5/5 and avg col of that point 2+1/2,
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Star Strider
am 24 Aug. 2016
This works:
M = [2 5 3 500 4 5
3 4 2 2 3 5
4 5 5 1 2 2];
[r,c] = find(M == 500);
RowAvg = mean(M(r,M(r,:)~=500));
ColAvg = mean(M(M(:,c)~=500,c));
3 Kommentare
Star Strider
am 24 Aug. 2016
The ‘r’ and ‘c’ are the row and column indices of ‘500’ respectively.
In the event of more than one ‘500’, the easiest way to modify my code would be to add a loop:
M = [2 5 3 500 4 5
3 4 2 2 3 5
4 5 500 1 2 2];
[r,c] = find(M == 500);
for k1 = 1:size(r,1)
RowAvg(k1) = mean(M(r(k1),M(r(k1),:)~=500));
ColAvg(k1) = mean(M(M(:,c(k1))~=500,c(k1)));
end
Here, every ‘[r,c]’ pair defines a specific value for ‘RowAvg’ and ‘ColAvg’.
This works if there is only one ‘500’ in any specific row or column. If there are more than one ‘500’ in any row or column, you have to decide how you want to deal with the second ‘500’.
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Thorsten
am 24 Aug. 2016
Bearbeitet: Thorsten
am 24 Aug. 2016
A = [2 5 3 500 4 5; 3 4 2 2 3 5; 4 5 5 1 2 2];
[i, j] = ind2sub(size(A), find(A==500));
m1 = mean(A(i, ~ismember(1:size(A,2), j)));
m2 = mean(A(~ismember(1:size(A,1), i), j));
A(i,j) = (m1 + m2)/2;
or
idx = A == 500
A(idx) = nan;
A(idx) = mean([nanmean(A(:, any(idx, 1))) nanmean(A(any(idx, 2), :), 2)])
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