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How to Write all of an if-statement in a Single Lline?

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Rightia Rollmann
Rightia Rollmann am 16 Aug. 2016
Bearbeitet: Angelo Yeo am 8 Jul. 2023
Is there any way to write all of an if-statement in a single line?
if A == 1 B = 2 elseif B = 3 end

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 16 Aug. 2016
Bearbeitet: Azzi Abdelmalek am 16 Aug. 2016
if A ==1 B = 2, else B = 3, end
But what is the aim of this?
  5 Kommentare
Steven Lord
Steven Lord am 13 Apr. 2021
Consider writing a "logme" function.
function logme(messageToLog)
verbose = true;
if verbose
fprintf('%s', messageToLog)
end
end
Now your code will contain calls to logme.
logme("Diagnostic message #1")
If you want to run without displaying these messages, change the definition of verbose inside logme. You could potentially also modify logme to log those messages not to the screen but to a log file without changing the callers of logme.
Angelo Yeo
Angelo Yeo am 8 Jul. 2023
Bearbeitet: Angelo Yeo am 8 Jul. 2023
If you want to set up if-else statement with a single line and make it into an inline funciton, you can think of such a thing.
ternary = @(varargin) varargin{end - varargin{1}};
ternary(true,'yes','no') % If the first argument is true, the result becomes 'yes'
ans = 'yes'
ternary(false,'yes','no') % If the first argument is false, the result becomes 'no'
ans = 'no'

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Weitere Antworten (1)

KarlHoff
KarlHoff am 20 Okt. 2021
You can employ logicals as factors toggling between 0 and 1:
B = 2 + 1*(A~=1);
%or
%B = 3 + (-1)*(A==1) ; % just roles reversed - depending on taste
This approach works whenever your if-statement just discriminates between two versions of a single assignment to one and the same variable as your example does.
I personally find this particular useful if there is a base value (here 2) and some delta added conditionally (here, +1 to obtain 3). You can also extend for further conditions.
  2 Kommentare
Reno Filla
Reno Filla am 9 Dez. 2021
The problem is if you want to get NaN on the case of, for example A==1
2+NaN*(A==1) doesnt work because 0*NaN return NaN just as 1*NaN does.
Also employing the NaN() function like
2+NaN(A==1) doesnt help since NaN(0) returns [] and canot be added to a scalar.
Any ideas?
KarlHoff
KarlHoff am 10 Dez. 2021
How about
0/(A-1) + 3 %returns different numeric values for different A ~= 1
or
0/( (A==1)-1 ) + 3 % returns 3 for all A ~= 1

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