hi . i have n observation z1 , z2, z3 , ...... zn that is numerical value and not ordered . i need partion it to interval as following

z1,z2,...,zn % known data 
a=min(z)
b=max(z)
k =3.322*log(n) %such that k number of interval 
L= (max(z)-min(z))/k %such that L is length of each interval

i need the program display interval as following

u1=(a,a+L)
u2=(a+L,a+2*L)
.
.
.
uend=( a+end*L,b)

Answer 1

[Image Analyst]

Another way is to use linspace():

n = 50;
z = 1000 * rand(1, n); % Sample data
a=min(z)
b=max(z)
k =3.322*log(n) % such that k is the number of intervals
L= (max(z)-min(z))/k %such that L is length of each interval

% Here is my solution:
intK = round(k)
uMatrix = [linspace(a, b-L, intK)', linspace(a+L, b, intK)']

[mohammed elmenshawy]

thank u very much , i need getting the average for this interval

[Image Analyst]

The average what ? The average interval length is L. What else is there to take the average of ?

Answer 2

[Azzi Abdelmalek]

Edit

a=min(z)
b=max(z)
k =3.322*log(n) %such that k number of interval 
L= (max(z)-min(z))/k 
m=fix((b-a)/L)
out=[cell2mat(arrayfun(@(x) [a+x*L,a+(x+1)*L],(0:m-1)','un',0));a+m*L,b]

[mohammed elmenshawy]

thank u very much , i need getting the average for this interval