meshgrid or ngrid?

6 Ansichten (letzte 30 Tage)
ttopal
ttopal am 9 Aug. 2016
Beantwortet: KSSV am 9 Aug. 2016
Hi, I have lately started to use meshgrid and ngrid thanks to the answer to my previous question. But I can not find a way to transform this code to either of them. Here on this code I have one calculationPoint, which normally has to be a meshgrid of -20:20 on both X and Y direction. Any suggestion on how to proceed would be appreciated.
clc;
S = 21;
t = linspace(-pi,pi,S);
knownPoints = [cos(t);sin(t)]; %(x,y)
f = exp(1i*t);
d = zeros (1,S);
calculationPoint = [10;9];
for idx=1:S
tmp1 = calculationPoint(1,1)-knownPoints(1,idx);
tmp2 = calculationPoint(2,1)-knownPoints(2,idx);
d(idx) = sqrt(tmp1^2+tmp2^2);
end
g = d.^2 + 1./d.^3;
z = 1/S*sum(g.*f); % z function is of parameter calculation point

Antworten (1)

KSSV
KSSV am 9 Aug. 2016
Your d, g are arrays of same size as t....You can use mesh grid on d/g... Are you looking for some thing like below?
clc;
S = 21;
t = linspace(-pi,pi,S);
knownPoints = [cos(t);sin(t)]; %(x,y)
f = exp(1i*t);
d = zeros (1,S);
calculationPoint = [10;9];
for idx=1:S
tmp1 = calculationPoint(1,1)-knownPoints(1,idx);
tmp2 = calculationPoint(2,1)-knownPoints(2,idx);
d(idx) = sqrt(tmp1^2+tmp2^2);
end
g = d.^2 + 1./d.^3;
[T,G] = meshgrid(t,g) ;
z = 1/S*sum(g.*f); % z function is of parameter calculation point

Kategorien

Mehr zu Contour Plots finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by