Remove cell that contains strings of another cell array
55 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
chlor thanks
am 8 Aug. 2016
Beantwortet: Sean Mahnken
am 28 Mär. 2019
Input:
a={'Time12:30','Time12:40','Time1:40', 'Time2:40'};
b={'12:', '1:'};
Wanted Output: (delete from "a" all cells containing string listed in "b")
a={'Time2:40'}
I have tried:
for k = 1 : length(a)
for kk = 1 : length(b)
if any(~ismember(b{kk}, a{k}))
a(k) = [];
break;
end
end
end
However this gives me error of such:
Index exceeds matrix dimensions.
I am confused by the error and any guidance is appreciated! Thank you for reading my post.
0 Kommentare
Akzeptierte Antwort
James Tursa
am 8 Aug. 2016
Bearbeitet: James Tursa
am 8 Aug. 2016
You are changing the size of a in the loop with this line:
a(k) = [];
So subsequent iteration indexes that depend on the length of a will fail. Maybe save the indexes to delete in the loop, and then delete them all at once at the end. E.g., something like this:
a={'Time12:30','Time12:40','Time1:40', 'Time2:40'};
b={'12:', '1:'};
x = false(size(a)); % <-- Indexes to delete, start out nobody deleted
for k=1:numel(b)
x = x | ~cellfun(@isempty,strfind(a,b{k})); % <-- Flag the ones that b{k} matches
end
a(x) = []; % <-- Delete all the flagged lines at once
Weitere Antworten (2)
Sean Mahnken
am 28 Mär. 2019
You should be able to just do the k loop backwards:
for k = length(a):-1:1
for kk = 1 : length(b)
if any(~ismember(b{kk}, a{k}))
a(k) = [];
break;
end
end
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Calendar finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!