Sum of functions with function handle

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Madeleine Hermann
Madeleine Hermann am 24 Jul. 2016
I have problems to understand function handle @. I have been away from Matlab for many years (almost 20 years) and now I’m back as a supervisor in a FEM-course. I’m trying to use my old code, but I never used function handles and to integrate we used a function called quad and called the function to be integrated by a string. Now to the problem: I have a function which contains the functions to be integrated:
function [dnhdn] = dnhdn(r,c,x)
global ata
dnhdn= dshape(r,x).*(((height(x)).^3)/(12*ata)).*dshape(c,x);
height is a function of x for ex. h=h0*exp(-10*x); dshape is a shapefuntion of x (an array with three alternative assign by r and c)
function [Be] = dshape(i,x)
% The function calculate the differated shapefunctions for the quadratic
% element.
global xi xj xk L
Be1=[(2/L^2)*(2*x-xj-xk);(-4/L^2)*(2*x-xi-xk);(2/L^2)*(2*x-xi-xj)];
Be=Be1(i,:);
dnhdn is the function to be integrated.
Using q = integral(fun,xmin,xmax) Fun must be assign with function handle, @(x). How do I manage to make a function with function handle from a product of several function? My fun is going to be dnhdn and I really like to have height and dshape in separate functions. I hope that someone understand my question and I'm looking forward to an answer. Please add a simple code just to clarify how to do. Best regard /Madeleine

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 24 Jul. 2016
If r and c are constants relative to the integration, and x is the variable of integration, then:
fun = @(x) dnhdn(r, c, x);
  1 Kommentar
Madeleine Hermann
Madeleine Hermann am 24 Jul. 2016
Thanks, very easy. Here a found problem that did not exist. Madeleine

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