Output argument not assigned during call

1 Ansicht (letzte 30 Tage)
Kiruba Raji.I
Kiruba Raji.I am 23 Jul. 2016
Beantwortet: Geoff Hayes am 23 Jul. 2016
function [S1]= PCNN(S)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
Alpha_F=0.1;
Alpha_L=1.0;
Alpha_T=1.0;
V_F=0.5;
V_L=0.2;
V_T=20.0;
Beta=0.1;
Num=100;
W=[0.5 1 0.5;1 0 1; 0.5 1 0.5];
M=[0.5 1 0.5;1 0 1; 0.5 1 0.5];
F=zeros(size(S));
L=F;
Y=F;
U=F;
T=ones(size(S));
S=im2double(S);
for n=1:Num
F=exp(-Alpha_F)*F + V_F * conv2(Y,W,'same')+S;
L=exp(-Alpha_L)* L+V_L * conv2(Y,M,'same');
U=F.*(1+Beta* L);
Y=double(U>T);
T=exp(-Alpha_T)*T+V_T*Y;
end
end
Script
I=imread('d:\segleaf\i1.jpg');
[I1]=PCNN(I);

Akzeptierte Antwort

Geoff Hayes
Geoff Hayes am 23 Jul. 2016
Kiruba - look at your function signature
function [S1]= PCNN(S)
The output parameter is S1 yet nowhere in your code is this variable declared. You will need to determine which of the variable in your for loop corresponds to S1 and initialize S1 to this variable.

Weitere Antworten (1)

the cyclist
the cyclist am 23 Jul. 2016
The output variable S1 is never assigned in the function.

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