complex sine graph plotting I need help
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my complex sine graph is 1050 points. I want it to be just 100 points for some other math calculations. here is the function. can someone please fix it for me so that stpFunc is 100 instead of 1050 and still graphs similarly, thanks a ton!
n = 1050;
w = [0:.005:1-0.005]';
w=repmat(w,5,1); %repmat(w,10,1);
w=[zeros(50,1);w];
t=[zeros(50,1)];
for i=1:5 %10
t=[t;i*ones(200,1)];
end
stpFunc = sin(2*pi*w.*t);
complex_sine = stpFunc'
figure; plot(stpFunc,'linewidth',3);
2 Kommentare
Azzi Abdelmalek
am 22 Jul. 2016
Bearbeitet: Azzi Abdelmalek
am 22 Jul. 2016
Can you explain what your code is doing?
Osita Onyejekwe
am 22 Jul. 2016
Antworten (2)
Star Strider
am 22 Jul. 2016
I do not understand everything you are doing. If you want ‘w’ to have a length of 100, use the linspace function:
w = linspace(0, 1, 100);
I cannot follow what you are doing with the rest of your code, so you will have to change it to work with the new ‘w’.
4 Kommentare
Osita Onyejekwe
am 22 Jul. 2016
Star Strider
am 22 Jul. 2016
This interpolates the original to be a length of 100, but even using the 'spline' interpolation method, the undersampling does not reproduce the original look of the function.
n = 1050;
w = [0:.005:1-0.005]';
w=repmat(w,5,1); %repmat(w,10,1);
w=[zeros(50,1);w];
t=[zeros(50,1)];
for i=1:5 %10
t=[t;i*ones(200,1)];
end
stpFunc0 = sin(2*pi*w.*t); % Original ‘stpFunc’
stpFunci = linspace(1, length(stpFunc0), 100); % Interpolation Vector
stpFunc = interp1([1:length(stpFunc0)],stpFunc0,stpFunci,'spline'); % Interpolated ‘stpFunc’
complex_sine = stpFunc';
figure; plot(stpFunc,'linewidth',3);
Osita Onyejekwe
am 22 Jul. 2016
Star Strider
am 22 Jul. 2016
My pleasure!
If my Answer solved your problem, please Accept it.
Osita Onyejekwe
am 22 Jul. 2016
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