Why does my for-loop nested in an if-statement not work?

3 Ansichten (letzte 30 Tage)
F S
F S am 20 Jul. 2016
Kommentiert: F S am 20 Jul. 2016
I have an for-loop inside an if-statement nested again in another for-loop (I know sounds complicated, example below), which seems to run perfeclty, as long as until the loop is called the SECOND time. Then it gives me the error:
Index exceeds matrix dimensions.
Error in code (line 50)
imb=squeeze(B_proc(n,:,:));
Does anybody have an idea why?
Here the simplified for-if-for-loop:
k=1;
for i=2:length(proc_core)
proc=cell2mat(proc_core(i,2));
sz=size(proc);
l=sz(1);
vs=cell2mat(proc_core(i,3));
if sz(2)==512 && sz(3)==512 && vs==2.5
kl=k+l-1;
Core(k:kl,:,:)=proc;
k=k+l;
elseif vs==2.5
for n=1:length(proc)
imb=squeeze(proc(n,:,:));
imb=imresize(imb,[512 512]);
Core(k,:,:)=imb;
k=k+1;
end
end
end

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 20 Jul. 2016
length(proc) is defined as:
if isempty(proc)
length = 0
else
length = max(size(proc))
end
You, however, used length(proc) as if it were defined as size(proc,1) . If one of the other dimensions of proc is bigger than the number of rows then that bigger dimension is the length.
  1 Kommentar
F S
F S am 20 Jul. 2016
thanks a lot! I suspected there was some other bug in there but I just couldn't find it.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by