Want to convert hourly Data into Daily Mean
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Bikiran Das
am 19 Jul. 2016
Kommentiert: Bikiran Das
am 20 Jul. 2016
My Data Has hourly recording from date 27th March 2013 to 30 Jan 2015 the Data for 28th March 2013 to 29th Jan 2015 has data for every hour and i.e. daily records are 24 in numbers where as for 27th of March 2013 the data is recorded from 06:00:00 HRS to 23:00:00 Hrs and similarly for 30th Jan 2015 the recorded data is from 00:00:00 HRS to 05:00:00 HRS.
Please help me getting the daily average for the data with single date 1st column.
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Azzi Abdelmalek
am 19 Jul. 2016
%--------------Example----------------------------------
d=datenum('28-03-2013 07:00:00','dd-mm-yyyy HH:MM:SS'):1/24:datenum('30-01-2015 05:00:00','dd-mm-yyyy HH:MM:SS')
M=[d' randi(10000,size(d'))]
%--------------------------The code--------------------
f=datevec(d)
g=f(:,1:3)
s,ii,jj]=unique(g,'rows')
v=accumarray(jj,(1:numel(jj))',[],@mean)
dates=datestr(d(ii))
out=[cellstr(datestr(d(ii))) num2cell(v)]
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Azzi Abdelmalek
am 19 Jul. 2016
load DATA
load time
d=datenum(time)
M=[d Data]
f=datevec(d)
g=f(:,1:3)
[s,ii,jj]=unique(g,'rows')
v=accumarray(jj,(1:numel(jj))',[],@(x) {nanmean(Data(x,:),1)});
dates=datestr(d(ii))
out=[cellstr(datestr(d(ii))) num2cell(v)]
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